9x^2-50x+18=0

Solution for 9x^2-50x+18=0 equation:

9x^2-50x+18=0

a = 9; b = -50; c = +18;
Δ = b2-4ac
Δ = -502-4·9·18
Δ = 1852
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1852}=\sqrt{4*463}=\sqrt{4}*\sqrt{463}=2\sqrt{463}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-50)-2\sqrt{463}}{2*9}=\frac{50-2\sqrt{463}}{18}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-50)+2\sqrt{463}}{2*9}=\frac{50+2\sqrt{463}}{18}
$